Solve 8+1/12+1/36=1/9

$$8 + \frac { 1 } { 12 } + \frac { 1 } { 36 } = \frac { 1 } { 9 }$$

Verify

Solution Steps

Convert 8 to fraction \frac{96}{12}.

$$\frac{96}{12}+\frac{1}{12}+\frac{1}{36}=\frac{1}{9}$$

Since \frac{96}{12} and \frac{1}{12} have the same denominator, add them by adding their numerators.

$$\frac{96+1}{12}+\frac{1}{36}=\frac{1}{9}$$

Add 96 and 1 to get 97.

$$\frac{97}{12}+\frac{1}{36}=\frac{1}{9}$$

Least common multiple of 12 and 36 is 36. Convert \frac{97}{12} and \frac{1}{36} to fractions with denominator 36.

$$\frac{291}{36}+\frac{1}{36}=\frac{1}{9}$$

Since \frac{291}{36} and \frac{1}{36} have the same denominator, add them by adding their numerators.

$$\frac{291+1}{36}=\frac{1}{9}$$

Add 291 and 1 to get 292.

$$\frac{292}{36}=\frac{1}{9}$$

Reduce the fraction \frac{292}{36} to lowest terms by extracting and canceling out 4.

$$\frac{73}{9}=\frac{1}{9}$$

Compare \frac{73}{9} and \frac{1}{9}.

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