Solve for y
y=\frac{x^{3}}{6}-\frac{x}{8}
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24y=4x^{3}-3x
Multiply both sides of the equation by 3.
\frac{24y}{24}=\frac{x\left(4x^{2}-3\right)}{24}
Divide both sides by 24.
y=\frac{x\left(4x^{2}-3\right)}{24}
Dividing by 24 undoes the multiplication by 24.
y=\frac{x^{3}}{6}-\frac{x}{8}
Divide x\left(4x^{2}-3\right) by 24.
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