Solve for x
x=\frac{7y}{3}-1
Solve for y
y=\frac{3\left(x+1\right)}{7}
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3x+3=7y
Swap sides so that all variable terms are on the left hand side.
3x=7y-3
Subtract 3 from both sides.
\frac{3x}{3}=\frac{7y-3}{3}
Divide both sides by 3.
x=\frac{7y-3}{3}
Dividing by 3 undoes the multiplication by 3.
x=\frac{7y}{3}-1
Divide 7y-3 by 3.
7y=3x+3
The equation is in standard form.
\frac{7y}{7}=\frac{3x+3}{7}
Divide both sides by 7.
y=\frac{3x+3}{7}
Dividing by 7 undoes the multiplication by 7.
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