Solve for a
a=\frac{7x+10}{3}
Solve for x
x=\frac{3a-10}{7}
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3a-2=7x+8
Swap sides so that all variable terms are on the left hand side.
3a=7x+8+2
Add 2 to both sides.
3a=7x+10
Add 8 and 2 to get 10.
\frac{3a}{3}=\frac{7x+10}{3}
Divide both sides by 3.
a=\frac{7x+10}{3}
Dividing by 3 undoes the multiplication by 3.
7x=3a-2-8
Subtract 8 from both sides.
7x=3a-10
Subtract 8 from -2 to get -10.
\frac{7x}{7}=\frac{3a-10}{7}
Divide both sides by 7.
x=\frac{3a-10}{7}
Dividing by 7 undoes the multiplication by 7.
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\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
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Limits
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