Solve for x
x = \frac{\sqrt[3]{10} + 6}{7} \approx 1.164919241
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7x+\sqrt[3]{-10}=9-3
Multiply 5 and -2 to get -10.
7x+\sqrt[3]{-10}=6
Subtract 3 from 9 to get 6.
7x=6-\sqrt[3]{-10}
Subtract \sqrt[3]{-10} from both sides.
\frac{7x}{7}=\frac{\sqrt[3]{10}+6}{7}
Divide both sides by 7.
x=\frac{\sqrt[3]{10}+6}{7}
Dividing by 7 undoes the multiplication by 7.
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