Solve for y
y=\frac{x^{3}}{28x+1}
x\neq -\frac{1}{28}
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28xy=x^{3}-y
Multiply 7 and 4 to get 28.
28xy+y=x^{3}
Add y to both sides.
\left(28x+1\right)y=x^{3}
Combine all terms containing y.
\frac{\left(28x+1\right)y}{28x+1}=\frac{x^{3}}{28x+1}
Divide both sides by 28x+1.
y=\frac{x^{3}}{28x+1}
Dividing by 28x+1 undoes the multiplication by 28x+1.
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Limits
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