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Differentiate w.r.t. x_5279
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\begin{array}{c}\phantom{\times9999}7889\\\underline{\times\phantom{9999}5279}\\\end{array}
First line up the numbers vertically and match the places from the right like this.
\begin{array}{c}\phantom{\times9999}7889\\\underline{\times\phantom{9999}5279}\\\phantom{\times999}71001\\\end{array}
Now multiply the first number with the 1^{st} digit in 2^{nd} number to get intermediate results. That is Multiply 7889 with 9. Write the result 71001 at the end leaving 0 spaces to the right like this.
\begin{array}{c}\phantom{\times9999}7889\\\underline{\times\phantom{9999}5279}\\\phantom{\times999}71001\\\phantom{\times99}55223\phantom{9}\\\end{array}
Now multiply the first number with the 2^{nd} digit in 2^{nd} number to get intermediate results. That is Multiply 7889 with 7. Write the result 55223 at the end leaving 1 spaces to the right like this.
\begin{array}{c}\phantom{\times9999}7889\\\underline{\times\phantom{9999}5279}\\\phantom{\times999}71001\\\phantom{\times99}55223\phantom{9}\\\phantom{\times9}15778\phantom{99}\\\end{array}
Now multiply the first number with the 3^{rd} digit in 2^{nd} number to get intermediate results. That is Multiply 7889 with 2. Write the result 15778 at the end leaving 2 spaces to the right like this.
\begin{array}{c}\phantom{\times9999}7889\\\underline{\times\phantom{9999}5279}\\\phantom{\times999}71001\\\phantom{\times99}55223\phantom{9}\\\phantom{\times9}15778\phantom{99}\\\underline{\phantom{\times}39445\phantom{999}}\\\end{array}
Now multiply the first number with the 4^{th} digit in 2^{nd} number to get intermediate results. That is Multiply 7889 with 5. Write the result 39445 at the end leaving 3 spaces to the right like this.
\begin{array}{c}\phantom{\times9999}7889\\\underline{\times\phantom{9999}5279}\\\phantom{\times999}71001\\\phantom{\times99}55223\phantom{9}\\\phantom{\times9}15778\phantom{99}\\\underline{\phantom{\times}39445\phantom{999}}\\\phantom{\times}41646031\end{array}
Now add the intermediate results to get final answer.
7889x_{5279}^{1-1}
The derivative of ax^{n} is nax^{n-1}.
7889x_{5279}^{0}
Subtract 1 from 1.
7889\times 1
For any term t except 0, t^{0}=1.
7889
For any term t, t\times 1=t and 1t=t.