Solve 78+[(5x+3)*3-15+4*(5-2x)]=99

$$78 + [ ( 5 x + 3 ) \cdot 3 - 15 + 4 \cdot ( 5 - 2 x ) ] = 99$$

Solve for x

$$x=1$$

Steps for Solving Linear Equation

Use the distributive property to multiply 5x+3 by 3.

$$78+15x+9-15+4\left(5-2x\right)=99$$

Add 78 and 9 to get 87.

$$87+15x-15+4\left(5-2x\right)=99$$

Subtract 15 from 87 to get 72.

$$72+15x+4\left(5-2x\right)=99$$

Use the distributive property to multiply 4 by 5-2x.

$$72+15x+20-8x=99$$

Add 72 and 20 to get 92.

$$92+15x-8x=99$$

Combine 15x and -8x to get 7x.

$$92+7x=99$$

Subtract 92 from both sides.

$$7x=99-92$$

Subtract 92 from 99 to get 7.

$$7x=7$$

Divide both sides by 7.

$$x=\frac{7}{7}$$

Divide 7 by 7 to get 1.

$$x=1$$