Solve 7716-1-12+3[(1-6)^2-18])

$$7716 - 1 - 12 + 3 [ ( 1 - 6 ) ^ { 2 } - 18 ] )$$

Evaluate

$$7724$$

Solution Steps

Subtract 1 from 7716 to get 7715.

$$7715-12+3\left(\left(1-6\right)^{2}-18\right)$$

Subtract 12 from 7715 to get 7703.

$$7703+3\left(\left(1-6\right)^{2}-18\right)$$

Subtract 6 from 1 to get -5.

$$7703+3\left(\left(-5\right)^{2}-18\right)$$

Calculate -5 to the power of 2 and get 25.

$$7703+3\left(25-18\right)$$

Subtract 18 from 25 to get 7.

$$7703+3\times 7$$

Multiply 3 and 7 to get 21.

$$7703+21$$

Add 7703 and 21 to get 7724.

$$7724$$

Factor

$$2^{2}\times 1931$$