Solve 77+3*8div9+4*6-9+7div2+78

$$77+3 \times 8 \div 9+4 \times 6-9+7 \div 2+78$$

Evaluate

$$\frac{1057}{6}\approx 176.166666667$$

Solution Steps

Multiply 3 and 8 to get 24.

$$77+\frac{24}{9}+4\times 6-9+\frac{7}{2}+78$$

Reduce the fraction \frac{24}{9} to lowest terms by extracting and canceling out 3.

$$77+\frac{8}{3}+4\times 6-9+\frac{7}{2}+78$$

Convert 77 to fraction \frac{231}{3}.

$$\frac{231}{3}+\frac{8}{3}+4\times 6-9+\frac{7}{2}+78$$

Since \frac{231}{3} and \frac{8}{3} have the same denominator, add them by adding their numerators.

$$\frac{231+8}{3}+4\times 6-9+\frac{7}{2}+78$$

Add 231 and 8 to get 239.

$$\frac{239}{3}+4\times 6-9+\frac{7}{2}+78$$

Multiply 4 and 6 to get 24.

$$\frac{239}{3}+24-9+\frac{7}{2}+78$$

Convert 24 to fraction \frac{72}{3}.

$$\frac{239}{3}+\frac{72}{3}-9+\frac{7}{2}+78$$

Since \frac{239}{3} and \frac{72}{3} have the same denominator, add them by adding their numerators.

$$\frac{239+72}{3}-9+\frac{7}{2}+78$$

Add 239 and 72 to get 311.

$$\frac{311}{3}-9+\frac{7}{2}+78$$

Convert 9 to fraction \frac{27}{3}.

$$\frac{311}{3}-\frac{27}{3}+\frac{7}{2}+78$$

Since \frac{311}{3} and \frac{27}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{311-27}{3}+\frac{7}{2}+78$$

Subtract 27 from 311 to get 284.

$$\frac{284}{3}+\frac{7}{2}+78$$

Least common multiple of 3 and 2 is 6. Convert \frac{284}{3} and \frac{7}{2} to fractions with denominator 6.

$$\frac{568}{6}+\frac{21}{6}+78$$

Since \frac{568}{6} and \frac{21}{6} have the same denominator, add them by adding their numerators.

$$\frac{568+21}{6}+78$$

Add 568 and 21 to get 589.

$$\frac{589}{6}+78$$

Convert 78 to fraction \frac{468}{6}.

$$\frac{589}{6}+\frac{468}{6}$$

Since \frac{589}{6} and \frac{468}{6} have the same denominator, add them by adding their numerators.

$$\frac{589+468}{6}$$

Add 589 and 468 to get 1057.

$$\frac{1057}{6}$$

Factor

$$\frac{7 \cdot 151}{2 \cdot 3} = 176\frac{1}{6} = 176.16666666666666$$