Solve for x
x=\frac{32y}{75}+\frac{1}{25}
Solve for y
y=\frac{75x-3}{32}
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75x=3+32y
Add 32y to both sides.
75x=32y+3
The equation is in standard form.
\frac{75x}{75}=\frac{32y+3}{75}
Divide both sides by 75.
x=\frac{32y+3}{75}
Dividing by 75 undoes the multiplication by 75.
x=\frac{32y}{75}+\frac{1}{25}
Divide 3+32y by 75.
-32y=3-75x
Subtract 75x from both sides.
\frac{-32y}{-32}=\frac{3-75x}{-32}
Divide both sides by -32.
y=\frac{3-75x}{-32}
Dividing by -32 undoes the multiplication by -32.
y=\frac{75x-3}{32}
Divide 3-75x by -32.
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