Solve 750*5^-3+6^2((0,4)^-2-3^-1)=

$$750 \cdot 5 ^ { - 3 } + 6 ^ { 2 } ( ( 0,4 ) ^ { - 2 } - 3 ^ { - 1 } ) =$$

Evaluate

$$219$$

Solution Steps

Calculate 5 to the power of -3 and get \frac{1}{125}.

$$750\times \frac{1}{125}+6^{2}\left(0,4^{-2}-3^{-1}\right)$$

Multiply 750 and \frac{1}{125} to get 6.

$$6+6^{2}\left(0,4^{-2}-3^{-1}\right)$$

Calculate 6 to the power of 2 and get 36.

$$6+36\left(0,4^{-2}-3^{-1}\right)$$

Calculate 0,4 to the power of -2 and get 6,25.

$$6+36\left(6,25-3^{-1}\right)$$

Calculate 3 to the power of -1 and get \frac{1}{3}.

$$6+36\left(6,25-\frac{1}{3}\right)$$

Subtract \frac{1}{3} from 6,25 to get \frac{71}{12}.

$$6+36\times \frac{71}{12}$$

Multiply 36 and \frac{71}{12} to get 213.

$$6+213$$

Add 6 and 213 to get 219.

$$219$$

Factor

$$3\times 73$$