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75+x\times \frac{1.58\sqrt{35}}{\left(\sqrt{35}\right)^{2}}=75.523
Rationalize the denominator of \frac{1.58}{\sqrt{35}} by multiplying numerator and denominator by \sqrt{35}.
75+x\times \frac{1.58\sqrt{35}}{35}=75.523
The square of \sqrt{35} is 35.
75+x\times \frac{79}{1750}\sqrt{35}=75.523
Divide 1.58\sqrt{35} by 35 to get \frac{79}{1750}\sqrt{35}.
x\times \frac{79}{1750}\sqrt{35}=75.523-75
Subtract 75 from both sides.
x\times \frac{79}{1750}\sqrt{35}=0.523
Subtract 75 from 75.523 to get 0.523.
\frac{79\sqrt{35}}{1750}x=0.523
The equation is in standard form.
\frac{1750\times \frac{79\sqrt{35}}{1750}x}{79\sqrt{35}}=\frac{0.523\times 1750}{79\sqrt{35}}
Divide both sides by \frac{79}{1750}\sqrt{35}.
x=\frac{0.523\times 1750}{79\sqrt{35}}
Dividing by \frac{79}{1750}\sqrt{35} undoes the multiplication by \frac{79}{1750}\sqrt{35}.
x=\frac{523\sqrt{35}}{1580}
Divide 0.523 by \frac{79}{1750}\sqrt{35}.