Solve 75*[2*(1-03-05)+3*(06-05+010)]

$$75 \cdot [ 2 \cdot ( 1 - 03 - 05 ) + 3 \cdot ( 06 - 05 + 010 ) ]$$

Evaluate

$$150$$

Solution Steps

Multiply 0 and 3 to get 0.

$$75\left(2\left(1-0-0\times 5\right)+3\left(0\times 6-0\times 5+0\times 10\right)\right)$$

Subtract 0 from 1 to get 1.

$$75\left(2\left(1-0\times 5\right)+3\left(0\times 6-0\times 5+0\times 10\right)\right)$$

Multiply 0 and 5 to get 0.

$$75\left(2\left(1-0\right)+3\left(0\times 6-0\times 5+0\times 10\right)\right)$$

Subtract 0 from 1 to get 1.

$$75\left(2\times 1+3\left(0\times 6-0\times 5+0\times 10\right)\right)$$

Multiply 2 and 1 to get 2.

$$75\left(2+3\left(0\times 6-0\times 5+0\times 10\right)\right)$$

Multiply 0 and 6 to get 0.

$$75\left(2+3\left(0-0\times 5+0\times 10\right)\right)$$

Multiply 0 and 5 to get 0.

$$75\left(2+3\left(0-0+0\times 10\right)\right)$$

Subtracting 0 from itself leaves 0.

$$75\left(2+3\left(0+0\times 10\right)\right)$$

Multiply 0 and 10 to get 0.

$$75\left(2+3\left(0+0\right)\right)$$

Add 0 and 0 to get 0.

$$75\left(2+3\times 0\right)$$

Multiply 3 and 0 to get 0.

$$75\left(2+0\right)$$

Add 2 and 0 to get 2.

$$75\times 2$$

Multiply 75 and 2 to get 150.

$$150$$

Factor

$$2\times 3\times 5^{2}$$