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x+x_{2}\times \frac{1}{10}=75
Swap sides so that all variable terms are on the left hand side.
x=75-x_{2}\times \frac{1}{10}
Subtract x_{2}\times \frac{1}{10} from both sides.
x=75-\frac{1}{10}x_{2}
Multiply -1 and \frac{1}{10} to get -\frac{1}{10}.
x+x_{2}\times \frac{1}{10}=75
Swap sides so that all variable terms are on the left hand side.
x_{2}\times \frac{1}{10}=75-x
Subtract x from both sides.
\frac{1}{10}x_{2}=75-x
The equation is in standard form.
\frac{\frac{1}{10}x_{2}}{\frac{1}{10}}=\frac{75-x}{\frac{1}{10}}
Multiply both sides by 10.
x_{2}=\frac{75-x}{\frac{1}{10}}
Dividing by \frac{1}{10} undoes the multiplication by \frac{1}{10}.
x_{2}=750-10x
Divide 75-x by \frac{1}{10} by multiplying 75-x by the reciprocal of \frac{1}{10}.