Solve for t
t=\frac{1000000\ln(3)-2000000\ln(2)}{121}\approx -2377.537788858
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\frac{75}{100}=e^{0.000121t}
Divide both sides by 100.
\frac{3}{4}=e^{0.000121t}
Reduce the fraction \frac{75}{100} to lowest terms by extracting and canceling out 25.
e^{0.000121t}=\frac{3}{4}
Swap sides so that all variable terms are on the left hand side.
\log(e^{0.000121t})=\log(\frac{3}{4})
Take the logarithm of both sides of the equation.
0.000121t\log(e)=\log(\frac{3}{4})
The logarithm of a number raised to a power is the power times the logarithm of the number.
0.000121t=\frac{\log(\frac{3}{4})}{\log(e)}
Divide both sides by \log(e).
0.000121t=\log_{e}\left(\frac{3}{4}\right)
By the change-of-base formula \frac{\log(a)}{\log(b)}=\log_{b}\left(a\right).
t=\frac{\ln(\frac{3}{4})}{0.000121}
Divide both sides of the equation by 0.000121, which is the same as multiplying both sides by the reciprocal of the fraction.
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