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75+100-20x+x^{2}=\left(5+x\right)^{2}-25
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(10-x\right)^{2}.
175-20x+x^{2}=\left(5+x\right)^{2}-25
Add 75 and 100 to get 175.
175-20x+x^{2}=25+10x+x^{2}-25
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(5+x\right)^{2}.
175-20x+x^{2}=10x+x^{2}
Subtract 25 from 25 to get 0.
175-20x+x^{2}-10x=x^{2}
Subtract 10x from both sides.
175-30x+x^{2}=x^{2}
Combine -20x and -10x to get -30x.
175-30x+x^{2}-x^{2}=0
Subtract x^{2} from both sides.
175-30x=0
Combine x^{2} and -x^{2} to get 0.
-30x=-175
Subtract 175 from both sides. Anything subtracted from zero gives its negation.
x=\frac{-175}{-30}
Divide both sides by -30.
x=\frac{35}{6}
Reduce the fraction \frac{-175}{-30} to lowest terms by extracting and canceling out -5.