Solve for x
x=\frac{-24y-3}{71}
Solve for y
y=-\frac{71x}{24}-\frac{1}{8}
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72x+24y+3-x=0
Subtract x from both sides.
71x+24y+3=0
Combine 72x and -x to get 71x.
71x+3=-24y
Subtract 24y from both sides. Anything subtracted from zero gives its negation.
71x=-24y-3
Subtract 3 from both sides.
\frac{71x}{71}=\frac{-24y-3}{71}
Divide both sides by 71.
x=\frac{-24y-3}{71}
Dividing by 71 undoes the multiplication by 71.
24y+3=x-72x
Subtract 72x from both sides.
24y+3=-71x
Combine x and -72x to get -71x.
24y=-71x-3
Subtract 3 from both sides.
\frac{24y}{24}=\frac{-71x-3}{24}
Divide both sides by 24.
y=\frac{-71x-3}{24}
Dividing by 24 undoes the multiplication by 24.
y=-\frac{71x}{24}-\frac{1}{8}
Divide -71x-3 by 24.
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