Factor
\left(9z-1\right)\left(81z^{2}+9z-1\right)
Evaluate
729z^{3}-18z+1
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\left(9z-1\right)\left(81z^{2}+9z-1\right)
By Rational Root Theorem, all rational roots of a polynomial are in the form \frac{p}{q}, where p divides the constant term 1 and q divides the leading coefficient 729. One such root is \frac{1}{9}. Factor the polynomial by dividing it by 9z-1. Polynomial 81z^{2}+9z-1 is not factored since it does not have any rational roots.
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