Factor
\left(9z-1\right)\left(81z^{2}+9z+1\right)
Evaluate
729z^{3}-1
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\left(9z-1\right)\left(81z^{2}+9z+1\right)
Rewrite 729z^{3}-1 as \left(9z\right)^{3}-1^{3}. The difference of cubes can be factored using the rule: a^{3}-b^{3}=\left(a-b\right)\left(a^{2}+ab+b^{2}\right). Polynomial 81z^{2}+9z+1 is not factored since it does not have any rational roots.
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