Solve 72b^2+56^4+18b^2+44

$$72 b ^ { 2 } + 56 ^ { 4 } + 18 b ^ { 2 } + 44$$

Evaluate

$$90b^{2}+9834540$$

Solution Steps

Calculate 56 to the power of 4 and get 9834496.

$$72b^{2}+9834496+18b^{2}+44$$

Combine 72b^{2} and 18b^{2} to get 90b^{2}.

$$90b^{2}+9834496+44$$

Add 9834496 and 44 to get 9834540.

$$90b^{2}+9834540$$

Factor

$$30\left(3b^{2}+327818\right)$$

Solution Steps

Factor out 2.

$$2\left(45b^{2}+4917270\right)$$

Consider 36b^{2}+4917248+9b^{2}+22. Multiply and combine like terms.

$$45b^{2}+4917270$$

Consider 45b^{2}+4917270. Factor out 15.

$$15\left(3b^{2}+327818\right)$$

Rewrite the complete factored expression.

$$30\left(3b^{2}+327818\right)$$