Solve 72-m-n-89-11+m=

$$72 - m - n - 89 - 11 + m =$$

Evaluate

$$-n-28$$

Solution Steps

Subtract 89 from 72 to get -17.

$$-17-m-n-11+m$$

Subtract 11 from -17 to get -28.

$$-28-m-n+m$$

Combine -m and m to get 0.

$$-28-n$$

Differentiate w.r.t. n

$$-1$$

Steps Using Derivative Rule for Sum

Subtract 89 from 72 to get -17.

$$\frac{\mathrm{d}}{\mathrm{d}n}(-17-m-n-11+m)$$

Subtract 11 from -17 to get -28.

$$\frac{\mathrm{d}}{\mathrm{d}n}(-28-m-n+m)$$

Combine -m and m to get 0.

$$\frac{\mathrm{d}}{\mathrm{d}n}(-28-n)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$-n^{1-1}$$

Subtract 1 from 1.

$$-n^{0}$$

For any term t except 0, t^{0}=1.

$$-1$$