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\frac{72}{32}=q^{2}
Divide both sides by 32.
\frac{9}{4}=q^{2}
Reduce the fraction \frac{72}{32} to lowest terms by extracting and canceling out 8.
q^{2}=\frac{9}{4}
Swap sides so that all variable terms are on the left hand side.
q^{2}-\frac{9}{4}=0
Subtract \frac{9}{4} from both sides.
4q^{2}-9=0
Multiply both sides by 4.
\left(2q-3\right)\left(2q+3\right)=0
Consider 4q^{2}-9. Rewrite 4q^{2}-9 as \left(2q\right)^{2}-3^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).
q=\frac{3}{2} q=-\frac{3}{2}
To find equation solutions, solve 2q-3=0 and 2q+3=0.
\frac{72}{32}=q^{2}
Divide both sides by 32.
\frac{9}{4}=q^{2}
Reduce the fraction \frac{72}{32} to lowest terms by extracting and canceling out 8.
q^{2}=\frac{9}{4}
Swap sides so that all variable terms are on the left hand side.
q=\frac{3}{2} q=-\frac{3}{2}
Take the square root of both sides of the equation.
\frac{72}{32}=q^{2}
Divide both sides by 32.
\frac{9}{4}=q^{2}
Reduce the fraction \frac{72}{32} to lowest terms by extracting and canceling out 8.
q^{2}=\frac{9}{4}
Swap sides so that all variable terms are on the left hand side.
q^{2}-\frac{9}{4}=0
Subtract \frac{9}{4} from both sides.
q=\frac{0±\sqrt{0^{2}-4\left(-\frac{9}{4}\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -\frac{9}{4} for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
q=\frac{0±\sqrt{-4\left(-\frac{9}{4}\right)}}{2}
Square 0.
q=\frac{0±\sqrt{9}}{2}
Multiply -4 times -\frac{9}{4}.
q=\frac{0±3}{2}
Take the square root of 9.
q=\frac{3}{2}
Now solve the equation q=\frac{0±3}{2} when ± is plus. Divide 3 by 2.
q=-\frac{3}{2}
Now solve the equation q=\frac{0±3}{2} when ± is minus. Divide -3 by 2.
q=\frac{3}{2} q=-\frac{3}{2}
The equation is now solved.