Solve 71513/15+(-2134)+142/15+(-633/50)

$$715 \frac { 13 } { 15 } + ( - 2134 ) + 14 \frac { 2 } { 15 } + ( - 6 \frac { 33 } { 50 } )$$

Evaluate

$$-\frac{70533}{50}=-1410.66$$

Solution Steps

Multiply 715 and 15 to get 10725.

$$\frac{10725+13}{15}-2134+\frac{14\times 15+2}{15}-\frac{6\times 50+33}{50}$$

Add 10725 and 13 to get 10738.

$$\frac{10738}{15}-2134+\frac{14\times 15+2}{15}-\frac{6\times 50+33}{50}$$

Convert 2134 to fraction \frac{32010}{15}.

$$\frac{10738}{15}-\frac{32010}{15}+\frac{14\times 15+2}{15}-\frac{6\times 50+33}{50}$$

Since \frac{10738}{15} and \frac{32010}{15} have the same denominator, subtract them by subtracting their numerators.

$$\frac{10738-32010}{15}+\frac{14\times 15+2}{15}-\frac{6\times 50+33}{50}$$

Subtract 32010 from 10738 to get -21272.

$$-\frac{21272}{15}+\frac{14\times 15+2}{15}-\frac{6\times 50+33}{50}$$

Multiply 14 and 15 to get 210.

$$-\frac{21272}{15}+\frac{210+2}{15}-\frac{6\times 50+33}{50}$$

Add 210 and 2 to get 212.

$$-\frac{21272}{15}+\frac{212}{15}-\frac{6\times 50+33}{50}$$

Since -\frac{21272}{15} and \frac{212}{15} have the same denominator, add them by adding their numerators.

$$\frac{-21272+212}{15}-\frac{6\times 50+33}{50}$$

Add -21272 and 212 to get -21060.

$$\frac{-21060}{15}-\frac{6\times 50+33}{50}$$

Divide -21060 by 15 to get -1404.

$$-1404-\frac{6\times 50+33}{50}$$

Multiply 6 and 50 to get 300.

$$-1404-\frac{300+33}{50}$$

Add 300 and 33 to get 333.

$$-1404-\frac{333}{50}$$

Convert -1404 to fraction -\frac{70200}{50}.

$$-\frac{70200}{50}-\frac{333}{50}$$

Since -\frac{70200}{50} and \frac{333}{50} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-70200-333}{50}$$

Subtract 333 from -70200 to get -70533.

$$-\frac{70533}{50}$$

Factor

$$-\frac{70533}{50} = -1410\frac{33}{50} = -1410.66$$