Solve 710-(156800-218*710)div(48340-218^2)*218

$$710-(156800-218 \times 710) \div (48340- { 218 }^{ 2 } ) \times 218$$

Evaluate

$$\frac{17375}{102}\approx 170.343137255$$

Solution Steps

Multiply 218 and 710 to get 154780.

$$710-\frac{156800-154780}{48340-218^{2}}\times 218$$

Subtract 154780 from 156800 to get 2020.

$$710-\frac{2020}{48340-218^{2}}\times 218$$

Calculate 218 to the power of 2 and get 47524.

$$710-\frac{2020}{48340-47524}\times 218$$

Subtract 47524 from 48340 to get 816.

$$710-\frac{2020}{816}\times 218$$

Reduce the fraction \frac{2020}{816} to lowest terms by extracting and canceling out 4.

$$710-\frac{505}{204}\times 218$$

Express \frac{505}{204}\times 218 as a single fraction.

$$710-\frac{505\times 218}{204}$$

Multiply 505 and 218 to get 110090.

$$710-\frac{110090}{204}$$

Reduce the fraction \frac{110090}{204} to lowest terms by extracting and canceling out 2.

$$710-\frac{55045}{102}$$

Convert 710 to fraction \frac{72420}{102}.

$$\frac{72420}{102}-\frac{55045}{102}$$

Since \frac{72420}{102} and \frac{55045}{102} have the same denominator, subtract them by subtracting their numerators.

$$\frac{72420-55045}{102}$$

Subtract 55045 from 72420 to get 17375.

$$\frac{17375}{102}$$

Factor

$$\frac{5 ^ {3} \cdot 139}{2 \cdot 3 \cdot 17} = 170\frac{35}{102} = 170.34313725490196$$