Solve 71+0,6a=63+1,2a

$$71 + 0,6 a = 63 + 1,2 a$$

Solve for a

$$a=\frac{40}{3}\approx 13,333333333$$

Steps for Solving Linear Equation

Subtract 1,2a from both sides.

$$71+0,6a-1,2a=63$$

Combine 0,6a and -1,2a to get -0,6a.

$$71-0,6a=63$$

Subtract 71 from both sides.

$$-0,6a=63-71$$

Subtract 71 from 63 to get -8.

$$-0,6a=-8$$

Divide both sides by -0,6.

$$a=\frac{-8}{-0,6}$$

Expand \frac{-8}{-0,6} by multiplying both numerator and the denominator by 10.

$$a=\frac{-80}{-6}$$

Reduce the fraction \frac{-80}{-6} to lowest terms by extracting and canceling out -2.

$$a=\frac{40}{3}$$