Solve 70.2=(5^n-2^n)k_{2}

$$70.2 = ( 5 ^ { n } - 2 ^ { n } ) k _ { 2 }$$

Solve for k_2

$$k_{2}=-\frac{351}{5\left(2^{n}-5^{n}\right)}$$

$$n\neq 0$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$\left(5^{n}-2^{n}\right)k_{2}=70.2$$

Divide both sides by 5^{n}-2^{n}.

$$\frac{\left(5^{n}-2^{n}\right)k_{2}}{5^{n}-2^{n}}=\frac{70.2}{5^{n}-2^{n}}$$

Dividing by 5^{n}-2^{n} undoes the multiplication by 5^{n}-2^{n}.

$$k_{2}=\frac{70.2}{5^{n}-2^{n}}$$

Divide 70.2 by 5^{n}-2^{n}.

$$k_{2}=\frac{351}{5\left(5^{n}-2^{n}\right)}$$