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70=10+5x^{2}
Multiply 10 and 1 to get 10.
10+5x^{2}=70
Swap sides so that all variable terms are on the left hand side.
5x^{2}=70-10
Subtract 10 from both sides.
5x^{2}=60
Subtract 10 from 70 to get 60.
x^{2}=\frac{60}{5}
Divide both sides by 5.
x^{2}=12
Divide 60 by 5 to get 12.
x=2\sqrt{3} x=-2\sqrt{3}
Take the square root of both sides of the equation.
70=10+5x^{2}
Multiply 10 and 1 to get 10.
10+5x^{2}=70
Swap sides so that all variable terms are on the left hand side.
10+5x^{2}-70=0
Subtract 70 from both sides.
-60+5x^{2}=0
Subtract 70 from 10 to get -60.
5x^{2}-60=0
Quadratic equations like this one, with an x^{2} term but no x term, can still be solved using the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, once they are put in standard form: ax^{2}+bx+c=0.
x=\frac{0±\sqrt{0^{2}-4\times 5\left(-60\right)}}{2\times 5}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 5 for a, 0 for b, and -60 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\times 5\left(-60\right)}}{2\times 5}
Square 0.
x=\frac{0±\sqrt{-20\left(-60\right)}}{2\times 5}
Multiply -4 times 5.
x=\frac{0±\sqrt{1200}}{2\times 5}
Multiply -20 times -60.
x=\frac{0±20\sqrt{3}}{2\times 5}
Take the square root of 1200.
x=\frac{0±20\sqrt{3}}{10}
Multiply 2 times 5.
x=2\sqrt{3}
Now solve the equation x=\frac{0±20\sqrt{3}}{10} when ± is plus.
x=-2\sqrt{3}
Now solve the equation x=\frac{0±20\sqrt{3}}{10} when ± is minus.
x=2\sqrt{3} x=-2\sqrt{3}
The equation is now solved.