Solve 7.8%text{of}12.5+2.5%text{of}161=?

$$7.8 \% \text { of } 12.5 + 2.5 \% \text { of } 161 = ?$$

Evaluate

$$5$$

Solution Steps

Expand \frac{7.8}{100} by multiplying both numerator and the denominator by 10.

$$\frac{78}{1000}\times 12.5+\frac{2.5}{100}\times 161$$

Reduce the fraction \frac{78}{1000} to lowest terms by extracting and canceling out 2.

$$\frac{39}{500}\times 12.5+\frac{2.5}{100}\times 161$$

Convert decimal number 12.5 to fraction \frac{125}{10}. Reduce the fraction \frac{125}{10} to lowest terms by extracting and canceling out 5.

$$\frac{39}{500}\times \frac{25}{2}+\frac{2.5}{100}\times 161$$

Multiply \frac{39}{500} times \frac{25}{2} by multiplying numerator times numerator and denominator times denominator.

$$\frac{39\times 25}{500\times 2}+\frac{2.5}{100}\times 161$$

Do the multiplications in the fraction \frac{39\times 25}{500\times 2}.

$$\frac{975}{1000}+\frac{2.5}{100}\times 161$$

Reduce the fraction \frac{975}{1000} to lowest terms by extracting and canceling out 25.

$$\frac{39}{40}+\frac{2.5}{100}\times 161$$

Expand \frac{2.5}{100} by multiplying both numerator and the denominator by 10.

$$\frac{39}{40}+\frac{25}{1000}\times 161$$

Reduce the fraction \frac{25}{1000} to lowest terms by extracting and canceling out 25.

$$\frac{39}{40}+\frac{1}{40}\times 161$$

Multiply \frac{1}{40} and 161 to get \frac{161}{40}.

$$\frac{39}{40}+\frac{161}{40}$$

Since \frac{39}{40} and \frac{161}{40} have the same denominator, add them by adding their numerators.

$$\frac{39+161}{40}$$

Add 39 and 161 to get 200.

$$\frac{200}{40}$$

Divide 200 by 40 to get 5.

$$5$$

Factor

$$5$$