Solve 7-4(-9/2+3)=-2left(-9/2-2right)

$$7-4(- \frac{ 9 }{ 2 } +3) = -2 \left( - \frac{ 9 }{ 2 } -2 \right)$$

Verify

Solution Steps

Convert 3 to fraction \frac{6}{2}.

$$7-4\left(-\frac{9}{2}+\frac{6}{2}\right)=-2\left(-\frac{9}{2}-2\right)$$

Since -\frac{9}{2} and \frac{6}{2} have the same denominator, add them by adding their numerators.

$$7-4\times \frac{-9+6}{2}=-2\left(-\frac{9}{2}-2\right)$$

Add -9 and 6 to get -3.

$$7-4\left(-\frac{3}{2}\right)=-2\left(-\frac{9}{2}-2\right)$$

Express 4\left(-\frac{3}{2}\right) as a single fraction.

$$7-\frac{4\left(-3\right)}{2}=-2\left(-\frac{9}{2}-2\right)$$

Multiply 4 and -3 to get -12.

$$7-\frac{-12}{2}=-2\left(-\frac{9}{2}-2\right)$$

Divide -12 by 2 to get -6.

$$7-\left(-6\right)=-2\left(-\frac{9}{2}-2\right)$$

The opposite of -6 is 6.

$$7+6=-2\left(-\frac{9}{2}-2\right)$$

Add 7 and 6 to get 13.

$$13=-2\left(-\frac{9}{2}-2\right)$$

Convert 2 to fraction \frac{4}{2}.

$$13=-2\left(-\frac{9}{2}-\frac{4}{2}\right)$$

Since -\frac{9}{2} and \frac{4}{2} have the same denominator, subtract them by subtracting their numerators.

$$13=-2\times \frac{-9-4}{2}$$

Subtract 4 from -9 to get -13.

$$13=-2\left(-\frac{13}{2}\right)$$

Multiply -2 times -\frac{13}{2}.

$$13=13$$

Compare 13 and 13.

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