Solve 7-(14)+5*28+10/4

$$7-(14)+5 \cdot 28+ \frac{ 10 }{ 4 }$$

Evaluate

$$\frac{271}{2}=135.5$$

Solution Steps

Subtract 14 from 7 to get -7.

$$-7+5\times 28+\frac{10}{4}$$

Multiply 5 and 28 to get 140.

$$-7+140+\frac{10}{4}$$

Add -7 and 140 to get 133.

$$133+\frac{10}{4}$$

Reduce the fraction \frac{10}{4} to lowest terms by extracting and canceling out 2.

$$133+\frac{5}{2}$$

Convert 133 to fraction \frac{266}{2}.

$$\frac{266}{2}+\frac{5}{2}$$

Since \frac{266}{2} and \frac{5}{2} have the same denominator, add them by adding their numerators.

$$\frac{266+5}{2}$$

Add 266 and 5 to get 271.

$$\frac{271}{2}$$

Factor

$$\frac{271}{2} = 135\frac{1}{2} = 135.5$$