Solve for x
x>\frac{8}{5}
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7+40x>71
Multiply 8 and 5 to get 40.
40x>71-7
Subtract 7 from both sides.
40x>64
Subtract 7 from 71 to get 64.
x>\frac{64}{40}
Divide both sides by 40. Since 40 is positive, the inequality direction remains the same.
x>\frac{8}{5}
Reduce the fraction \frac{64}{40} to lowest terms by extracting and canceling out 8.
Examples
Quadratic equation
{ x } ^ { 2 } - 4 x - 5 = 0
Trigonometry
4 \sin \theta \cos \theta = 2 \sin \theta
Linear equation
y = 3x + 4
Arithmetic
699 * 533
Matrix
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Simultaneous equation
\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.
Differentiation
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
\int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d x
Limits
\lim _{x \rightarrow-3} \frac{x^{2}-9}{x^{2}+2 x-3}