Solve for x
x=\frac{7y-3}{2}
Solve for y
y=\frac{2x+3}{7}
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-2x=3-7y
Subtract 7y from both sides.
\frac{-2x}{-2}=\frac{3-7y}{-2}
Divide both sides by -2.
x=\frac{3-7y}{-2}
Dividing by -2 undoes the multiplication by -2.
x=\frac{7y-3}{2}
Divide 3-7y by -2.
7y=3+2x
Add 2x to both sides.
7y=2x+3
The equation is in standard form.
\frac{7y}{7}=\frac{2x+3}{7}
Divide both sides by 7.
y=\frac{2x+3}{7}
Dividing by 7 undoes the multiplication by 7.
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