Factor
7\left(y-4\right)\left(y^{2}+4y+16\right)
Evaluate
7\left(y^{3}-64\right)
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7\left(y^{3}-64\right)
Factor out 7.
\left(y-4\right)\left(y^{2}+4y+16\right)
Consider y^{3}-64. Rewrite y^{3}-64 as y^{3}-4^{3}. The difference of cubes can be factored using the rule: a^{3}-b^{3}=\left(a-b\right)\left(a^{2}+ab+b^{2}\right).
7\left(y-4\right)\left(y^{2}+4y+16\right)
Rewrite the complete factored expression. Polynomial y^{2}+4y+16 is not factored since it does not have any rational roots.
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