Solve for k
k=7-\frac{17}{x}
x\neq 0
Solve for x
x=\frac{17}{7-k}
k\neq 7
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7x-kx=17
Add 14 and 3 to get 17.
-kx=17-7x
Subtract 7x from both sides.
\left(-x\right)k=17-7x
The equation is in standard form.
\frac{\left(-x\right)k}{-x}=\frac{17-7x}{-x}
Divide both sides by -x.
k=\frac{17-7x}{-x}
Dividing by -x undoes the multiplication by -x.
k=7-\frac{17}{x}
Divide 17-7x by -x.
7x-kx=17
Add 14 and 3 to get 17.
\left(7-k\right)x=17
Combine all terms containing x.
\frac{\left(7-k\right)x}{7-k}=\frac{17}{7-k}
Divide both sides by 7-k.
x=\frac{17}{7-k}
Dividing by 7-k undoes the multiplication by 7-k.
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