Solve for x
x=\frac{9y+10}{7}
Solve for y
y=\frac{7x-10}{9}
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7x-10=9y
Add 9y to both sides. Anything plus zero gives itself.
7x=9y+10
Add 10 to both sides.
\frac{7x}{7}=\frac{9y+10}{7}
Divide both sides by 7.
x=\frac{9y+10}{7}
Dividing by 7 undoes the multiplication by 7.
-9y-10=-7x
Subtract 7x from both sides. Anything subtracted from zero gives its negation.
-9y=-7x+10
Add 10 to both sides.
-9y=10-7x
The equation is in standard form.
\frac{-9y}{-9}=\frac{10-7x}{-9}
Divide both sides by -9.
y=\frac{10-7x}{-9}
Dividing by -9 undoes the multiplication by -9.
y=\frac{7x-10}{9}
Divide -7x+10 by -9.
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\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
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Limits
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