Solve for x
x=\frac{4\left(y+3\right)}{7}
Solve for y
y=\frac{7x}{4}-3
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7x=12+4y
Add 4y to both sides.
7x=4y+12
The equation is in standard form.
\frac{7x}{7}=\frac{4y+12}{7}
Divide both sides by 7.
x=\frac{4y+12}{7}
Dividing by 7 undoes the multiplication by 7.
-4y=12-7x
Subtract 7x from both sides.
\frac{-4y}{-4}=\frac{12-7x}{-4}
Divide both sides by -4.
y=\frac{12-7x}{-4}
Dividing by -4 undoes the multiplication by -4.
y=\frac{7x}{4}-3
Divide 12-7x by -4.
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