Solve for x
x=\frac{3y+31}{7}
Solve for y
y=\frac{7x-31}{3}
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7x-31=3y
Add 3y to both sides. Anything plus zero gives itself.
7x=3y+31
Add 31 to both sides.
\frac{7x}{7}=\frac{3y+31}{7}
Divide both sides by 7.
x=\frac{3y+31}{7}
Dividing by 7 undoes the multiplication by 7.
-3y-31=-7x
Subtract 7x from both sides. Anything subtracted from zero gives its negation.
-3y=-7x+31
Add 31 to both sides.
-3y=31-7x
The equation is in standard form.
\frac{-3y}{-3}=\frac{31-7x}{-3}
Divide both sides by -3.
y=\frac{31-7x}{-3}
Dividing by -3 undoes the multiplication by -3.
y=\frac{7x-31}{3}
Divide -7x+31 by -3.
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