Solve for x
x=\frac{5\left(y+3\right)}{7}
Solve for y
y=\frac{7x}{5}-3
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7x=2y+15+3y
Add 3y to both sides.
7x=5y+15
Combine 2y and 3y to get 5y.
\frac{7x}{7}=\frac{5y+15}{7}
Divide both sides by 7.
x=\frac{5y+15}{7}
Dividing by 7 undoes the multiplication by 7.
7x-3y-2y=15
Subtract 2y from both sides.
7x-5y=15
Combine -3y and -2y to get -5y.
-5y=15-7x
Subtract 7x from both sides.
\frac{-5y}{-5}=\frac{15-7x}{-5}
Divide both sides by -5.
y=\frac{15-7x}{-5}
Dividing by -5 undoes the multiplication by -5.
y=\frac{7x}{5}-3
Divide 15-7x by -5.
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\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
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Limits
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