Solve 7xsqrt{3}-2/5=9

$$7 x \sqrt { 3 } - \frac { 2 } { 5 } = 9$$

Solve for x

$$x=\frac{47\sqrt{3}}{105}\approx 0.775298933$$

Steps for Solving Linear Equation

Add \frac{2}{5} to both sides.

$$7x\sqrt{3}=9+\frac{2}{5}$$

Convert 9 to fraction \frac{45}{5}.

$$7x\sqrt{3}=\frac{45}{5}+\frac{2}{5}$$

Since \frac{45}{5} and \frac{2}{5} have the same denominator, add them by adding their numerators.

$$7x\sqrt{3}=\frac{45+2}{5}$$

Add 45 and 2 to get 47.

$$7x\sqrt{3}=\frac{47}{5}$$

The equation is in standard form.

$$7\sqrt{3}x=\frac{47}{5}$$

Divide both sides by 7\sqrt{3}.

$$\frac{7\sqrt{3}x}{7\sqrt{3}}=\frac{\frac{47}{5}}{7\sqrt{3}}$$

Dividing by 7\sqrt{3} undoes the multiplication by 7\sqrt{3}.

$$x=\frac{\frac{47}{5}}{7\sqrt{3}}$$

Divide \frac{47}{5} by 7\sqrt{3}.

$$x=\frac{47\sqrt{3}}{105}$$