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7t^{2}-37t+12=0
Substitute t for x^{2}.
t=\frac{-\left(-37\right)±\sqrt{\left(-37\right)^{2}-4\times 7\times 12}}{2\times 7}
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Substitute 7 for a, -37 for b, and 12 for c in the quadratic formula.
t=\frac{37±\sqrt{1033}}{14}
Do the calculations.
t=\frac{\sqrt{1033}+37}{14} t=\frac{37-\sqrt{1033}}{14}
Solve the equation t=\frac{37±\sqrt{1033}}{14} when ± is plus and when ± is minus.
x=\frac{\sqrt{\frac{2\sqrt{1033}+74}{7}}}{2} x=-\frac{\sqrt{\frac{2\sqrt{1033}+74}{7}}}{2} x=\frac{\sqrt{\frac{74-2\sqrt{1033}}{7}}}{2} x=-\frac{\sqrt{\frac{74-2\sqrt{1033}}{7}}}{2}
Since x=t^{2}, the solutions are obtained by evaluating x=±\sqrt{t} for each t.