Solve 7x^2-y=3

$$7 x ^ { 2 } - y = 3$$

Solve for y

$$y=7x^{2}-3$$

Steps for Solving Linear Equation

Subtract 7x^{2} from both sides.

$$-y=3-7x^{2}$$

Divide both sides by -1.

$$\frac{-y}{-1}=\frac{3-7x^{2}}{-1}$$

Dividing by -1 undoes the multiplication by -1.

$$y=\frac{3-7x^{2}}{-1}$$

Divide 3-7x^{2} by -1.

$$y=7x^{2}-3$$

Solve for x (complex solution)

$$x=-\frac{\sqrt{7\left(y+3\right)}}{7}$$

$$x=\frac{\sqrt{7\left(y+3\right)}}{7}$$

Solve for x

$$x=\frac{\sqrt{7\left(y+3\right)}}{7}$$

$$x=-\frac{\sqrt{7\left(y+3\right)}}{7}\text{, }y\geq -3$$