Solve 7x^2=10

$$7 x ^ { 2 } = 10$$

Solve for x

$$x = \frac{\sqrt{70}}{7} \approx 1.195228609$$

$$x = -\frac{\sqrt{70}}{7} \approx -1.195228609$$

Steps by Finding Square Root

Divide both sides by 7.

$$x^{2}=\frac{10}{7}$$

Take the square root of both sides of the equation.

$$x=\frac{\sqrt{70}}{7} x=-\frac{\sqrt{70}}{7}$$

Steps Using the Quadratic Formula

Divide both sides by 7.

$$x^{2}=\frac{10}{7}$$

Subtract \frac{10}{7} from both sides.

$$x^{2}-\frac{10}{7}=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -\frac{10}{7} for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-\frac{10}{7}\right)}}{2}$$

Square 0.

$$x=\frac{0±\sqrt{-4\left(-\frac{10}{7}\right)}}{2}$$

Multiply -4 times -\frac{10}{7}.

$$x=\frac{0±\sqrt{\frac{40}{7}}}{2}$$

Take the square root of \frac{40}{7}.

$$x=\frac{0±\frac{2\sqrt{70}}{7}}{2}$$

Now solve the equation x=\frac{0±\frac{2\sqrt{70}}{7}}{2} when ± is plus.

$$x=\frac{\sqrt{70}}{7}$$

Now solve the equation x=\frac{0±\frac{2\sqrt{70}}{7}}{2} when ± is minus.

$$x=-\frac{\sqrt{70}}{7}$$

The equation is now solved.

$$x=\frac{\sqrt{70}}{7} x=-\frac{\sqrt{70}}{7}$$