Solve for x
x=\frac{16+3z-5y}{7}
Solve for y
y=\frac{16+3z-7x}{5}
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7x-3z=16-5y
Subtract 5y from both sides.
7x=16-5y+3z
Add 3z to both sides.
7x=16+3z-5y
The equation is in standard form.
\frac{7x}{7}=\frac{16+3z-5y}{7}
Divide both sides by 7.
x=\frac{16+3z-5y}{7}
Dividing by 7 undoes the multiplication by 7.
5y-3z=16-7x
Subtract 7x from both sides.
5y=16-7x+3z
Add 3z to both sides.
5y=16+3z-7x
The equation is in standard form.
\frac{5y}{5}=\frac{16+3z-7x}{5}
Divide both sides by 5.
y=\frac{16+3z-7x}{5}
Dividing by 5 undoes the multiplication by 5.
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\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
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Limits
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