Solve for x
x=\frac{2-3y}{7}
Solve for y
y=\frac{2-7x}{3}
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7x-2=-3y
Subtract 3y from both sides. Anything subtracted from zero gives its negation.
7x=-3y+2
Add 2 to both sides.
7x=2-3y
The equation is in standard form.
\frac{7x}{7}=\frac{2-3y}{7}
Divide both sides by 7.
x=\frac{2-3y}{7}
Dividing by 7 undoes the multiplication by 7.
3y-2=-7x
Subtract 7x from both sides. Anything subtracted from zero gives its negation.
3y=-7x+2
Add 2 to both sides.
3y=2-7x
The equation is in standard form.
\frac{3y}{3}=\frac{2-7x}{3}
Divide both sides by 3.
y=\frac{2-7x}{3}
Dividing by 3 undoes the multiplication by 3.
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