Solve 7x+3-5(10-3)+2/3*6/8

$$7 x + 3 - 5 ( 10 - 3 ) + \frac { 2 } { 3 } \cdot \frac { 6 } { 8 }$$

Evaluate

$$7x-\frac{63}{2}$$

Solution Steps

Subtract 3 from 10 to get 7.

$$7x+3-5\times 7+\frac{2}{3}\times \frac{6}{8}$$

Multiply 5 and 7 to get 35.

$$7x+3-35+\frac{2}{3}\times \frac{6}{8}$$

Subtract 35 from 3 to get -32.

$$7x-32+\frac{2}{3}\times \frac{6}{8}$$

Reduce the fraction \frac{6}{8} to lowest terms by extracting and canceling out 2.

$$7x-32+\frac{2}{3}\times \frac{3}{4}$$

Multiply \frac{2}{3} times \frac{3}{4} by multiplying numerator times numerator and denominator times denominator.

$$7x-32+\frac{2\times 3}{3\times 4}$$

Cancel out 3 in both numerator and denominator.

$$7x-32+\frac{2}{4}$$

Reduce the fraction \frac{2}{4} to lowest terms by extracting and canceling out 2.

$$7x-32+\frac{1}{2}$$

Convert -32 to fraction -\frac{64}{2}.

$$7x-\frac{64}{2}+\frac{1}{2}$$

Since -\frac{64}{2} and \frac{1}{2} have the same denominator, add them by adding their numerators.

$$7x+\frac{-64+1}{2}$$

Add -64 and 1 to get -63.

$$7x-\frac{63}{2}$$

Expand

$$7x-\frac{63}{2}$$

Solution Steps

Subtract 3 from 10 to get 7.

$$7x+3-5\times 7+\frac{2}{3}\times \frac{6}{8}$$

Multiply 5 and 7 to get 35.

$$7x+3-35+\frac{2}{3}\times \frac{6}{8}$$

Subtract 35 from 3 to get -32.

$$7x-32+\frac{2}{3}\times \frac{6}{8}$$

Reduce the fraction \frac{6}{8} to lowest terms by extracting and canceling out 2.

$$7x-32+\frac{2}{3}\times \frac{3}{4}$$

Multiply \frac{2}{3} times \frac{3}{4} by multiplying numerator times numerator and denominator times denominator.

$$7x-32+\frac{2\times 3}{3\times 4}$$

Cancel out 3 in both numerator and denominator.

$$7x-32+\frac{2}{4}$$

Reduce the fraction \frac{2}{4} to lowest terms by extracting and canceling out 2.

$$7x-32+\frac{1}{2}$$

Convert -32 to fraction -\frac{64}{2}.

$$7x-\frac{64}{2}+\frac{1}{2}$$

Since -\frac{64}{2} and \frac{1}{2} have the same denominator, add them by adding their numerators.

$$7x+\frac{-64+1}{2}$$

Add -64 and 1 to get -63.

$$7x-\frac{63}{2}$$