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7u^{2}-3u=0
Subtract 3u from both sides.
u\left(7u-3\right)=0
Factor out u.
u=0 u=\frac{3}{7}
To find equation solutions, solve u=0 and 7u-3=0.
7u^{2}-3u=0
Subtract 3u from both sides.
u=\frac{-\left(-3\right)±\sqrt{\left(-3\right)^{2}}}{2\times 7}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 7 for a, -3 for b, and 0 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
u=\frac{-\left(-3\right)±3}{2\times 7}
Take the square root of \left(-3\right)^{2}.
u=\frac{3±3}{2\times 7}
The opposite of -3 is 3.
u=\frac{3±3}{14}
Multiply 2 times 7.
u=\frac{6}{14}
Now solve the equation u=\frac{3±3}{14} when ± is plus. Add 3 to 3.
u=\frac{3}{7}
Reduce the fraction \frac{6}{14} to lowest terms by extracting and canceling out 2.
u=\frac{0}{14}
Now solve the equation u=\frac{3±3}{14} when ± is minus. Subtract 3 from 3.
u=0
Divide 0 by 14.
u=\frac{3}{7} u=0
The equation is now solved.
7u^{2}-3u=0
Subtract 3u from both sides.
\frac{7u^{2}-3u}{7}=\frac{0}{7}
Divide both sides by 7.
u^{2}-\frac{3}{7}u=\frac{0}{7}
Dividing by 7 undoes the multiplication by 7.
u^{2}-\frac{3}{7}u=0
Divide 0 by 7.
u^{2}-\frac{3}{7}u+\left(-\frac{3}{14}\right)^{2}=\left(-\frac{3}{14}\right)^{2}
Divide -\frac{3}{7}, the coefficient of the x term, by 2 to get -\frac{3}{14}. Then add the square of -\frac{3}{14} to both sides of the equation. This step makes the left hand side of the equation a perfect square.
u^{2}-\frac{3}{7}u+\frac{9}{196}=\frac{9}{196}
Square -\frac{3}{14} by squaring both the numerator and the denominator of the fraction.
\left(u-\frac{3}{14}\right)^{2}=\frac{9}{196}
Factor u^{2}-\frac{3}{7}u+\frac{9}{196}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(u-\frac{3}{14}\right)^{2}}=\sqrt{\frac{9}{196}}
Take the square root of both sides of the equation.
u-\frac{3}{14}=\frac{3}{14} u-\frac{3}{14}=-\frac{3}{14}
Simplify.
u=\frac{3}{7} u=0
Add \frac{3}{14} to both sides of the equation.