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7t^{2}=-1
Subtract 1 from both sides. Anything subtracted from zero gives its negation.
t^{2}=-\frac{1}{7}
Divide both sides by 7.
t=\frac{\sqrt{7}i}{7} t=-\frac{\sqrt{7}i}{7}
The equation is now solved.
7t^{2}+1=0
Quadratic equations like this one, with an x^{2} term but no x term, can still be solved using the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, once they are put in standard form: ax^{2}+bx+c=0.
t=\frac{0±\sqrt{0^{2}-4\times 7}}{2\times 7}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 7 for a, 0 for b, and 1 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
t=\frac{0±\sqrt{-4\times 7}}{2\times 7}
Square 0.
t=\frac{0±\sqrt{-28}}{2\times 7}
Multiply -4 times 7.
t=\frac{0±2\sqrt{7}i}{2\times 7}
Take the square root of -28.
t=\frac{0±2\sqrt{7}i}{14}
Multiply 2 times 7.
t=\frac{\sqrt{7}i}{7}
Now solve the equation t=\frac{0±2\sqrt{7}i}{14} when ± is plus.
t=-\frac{\sqrt{7}i}{7}
Now solve the equation t=\frac{0±2\sqrt{7}i}{14} when ± is minus.
t=\frac{\sqrt{7}i}{7} t=-\frac{\sqrt{7}i}{7}
The equation is now solved.