Solve 7n-(ah-3)=2n-5

$$7 n - ( a h - 3 ) = 2 n - 5$$

Solve for a

$$\left\{\begin{matrix}a=\frac{5n+8}{h}\text{, }&h\neq 0\\a\in \mathrm{R}\text{, }&n=-\frac{8}{5}\text{ and }h=0\end{matrix}\right.$$

Steps for Solving Linear Equation

To find the opposite of ah-3, find the opposite of each term.

$$7n-ah+3=2n-5$$

Subtract 7n from both sides.

$$-ah+3=2n-5-7n$$

Combine 2n and -7n to get -5n.

$$-ah+3=-5n-5$$

Subtract 3 from both sides.

$$-ah=-5n-5-3$$

Subtract 3 from -5 to get -8.

$$-ah=-5n-8$$

The equation is in standard form.

$$\left(-h\right)a=-5n-8$$

Divide both sides by -h.

$$\frac{\left(-h\right)a}{-h}=\frac{-5n-8}{-h}$$

Dividing by -h undoes the multiplication by -h.

$$a=\frac{-5n-8}{-h}$$

Divide -5n-8 by -h.

$$a=\frac{5n+8}{h}$$

Solve for h

$$\left\{\begin{matrix}h=\frac{5n+8}{a}\text{, }&a\neq 0\\h\in \mathrm{R}\text{, }&n=-\frac{8}{5}\text{ and }a=0\end{matrix}\right.$$

Steps for Solving Linear Equation

To find the opposite of ah-3, find the opposite of each term.

$$7n-ah+3=2n-5$$

Subtract 7n from both sides.

$$-ah+3=2n-5-7n$$

Combine 2n and -7n to get -5n.

$$-ah+3=-5n-5$$

Subtract 3 from both sides.

$$-ah=-5n-5-3$$

Subtract 3 from -5 to get -8.

$$-ah=-5n-8$$

The equation is in standard form.

$$\left(-a\right)h=-5n-8$$

Divide both sides by -a.

$$\frac{\left(-a\right)h}{-a}=\frac{-5n-8}{-a}$$

Dividing by -a undoes the multiplication by -a.

$$h=\frac{-5n-8}{-a}$$

Divide -5n-8 by -a.

$$h=\frac{5n+8}{a}$$