Solve 7h^2=42

$$7 h ^ { 2 } = 42$$

Solve for h

$$h=\sqrt{6}\approx 2.449489743$$

$$h=-\sqrt{6}\approx -2.449489743$$

Steps by Finding Square Root

Divide both sides by 7.

$$h^{2}=\frac{42}{7}$$

Divide 42 by 7 to get 6.

$$h^{2}=6$$

Take the square root of both sides of the equation.

$$h=\sqrt{6} h=-\sqrt{6}$$

Steps Using the Quadratic Formula

Divide both sides by 7.

$$h^{2}=\frac{42}{7}$$

Divide 42 by 7 to get 6.

$$h^{2}=6$$

Subtract 6 from both sides.

$$h^{2}-6=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -6 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$h=\frac{0±\sqrt{0^{2}-4\left(-6\right)}}{2}$$

Square 0.

$$h=\frac{0±\sqrt{-4\left(-6\right)}}{2}$$

Multiply -4 times -6.

$$h=\frac{0±\sqrt{24}}{2}$$

Take the square root of 24.

$$h=\frac{0±2\sqrt{6}}{2}$$

Now solve the equation h=\frac{0±2\sqrt{6}}{2} when ± is plus.

$$h=\sqrt{6}$$

Now solve the equation h=\frac{0±2\sqrt{6}}{2} when ± is minus.

$$h=-\sqrt{6}$$

The equation is now solved.

$$h=\sqrt{6} h=-\sqrt{6}$$